[CP2K-user] free energy of a trajectory starting from a transition state
jennifer
fuyu... at gmail.com
Sun Mar 29 21:55:50 UTC 2020
Dear Sirs.
I was trying to propagate trajectories using AIMD. I was asked to start
from a very high energy intermediate (similar energy as the transition
state) and see the product distribution.Then I need to get the activation
energy of the product formation from the high energy intermediate. So I
turn to MD as the following input setup. Then I get .ener file. I noticed
that the cons Qty is not constant and shift a lot at the end of the
trajectory. The final products are exactly what we would expect. I was
wondering if such way of running trajectories is scientific meaningful
regarding to predict product distribution* and whether the sum of kin and
pot is the free energy for the system. If not, how I can calculation the
free energy of MD simulation? *Last question is about Cons Qty. The
simulation starts after simple optimization without equilibration (which is
not possible cause our initial geometry is very high in energy and
equilibrium will lead it to pdt directly).But the Cons Qty tells us the
system is not fully equilibriumed so not reasonable.* How should I set up
MD from high energy intermediates/transition states?*
Thanks
* &MD*
* ENSEMBLE NVT *
* TEMPERATURE [K] 298.15 *
* TIMESTEP [fs] 0.5*
* STEPS 50000 *
* &THERMOSTAT*
* &NOSE*
* LENGTH 3*
* YOSHIDA 3*
* TIMECON 100.0*
* MTS 2*
* &END NOSE*
* &END THERMOSTAT *
*.ener*
*# Step Nr. Time[fs] Kin.[a.u.] Temp[K]
Pot.[a.u.] Cons Qty[a.u.] UsedTime[s] 0
0.000000 0.256346498 298.150000000 -1045.692256885
-1045.435438294 0.000000000 1 0.500000
0.251739701 292.791953385 -1045.687561911 -1045.435241155
16.035605922 2 1.000000 0.246770279
287.012147241 -1045.682578277 -1045.435120246 2.770686112
3 1.500000 0.243348534 283.032403503
-1045.679265278 -1045.435124527 2.778688506 4
2.000000 0.241726793 281.146199212 -1045.677792961
-1045.435171152 2.780995430 5 2.500000
0.241375809 280.737977961 -1045.677567598 -1045.435195062
2.386485098 6 3.000000 0.241853544
281.293619726 -1045.678163310 -1045.435211988 2.792329600
7 3.500000 0.242774676 282.364964657
-1045.679229318 -1045.435256191 2.387376870 8
4.000000 0.243440523 283.139394116 -1045.680060966
-1045.435321621 2.795848448 9 4.500000
0.242913307 282.526202203 -1045.679685038 -1045.435373115
2.785384228 10 5.000000 0.240445208
279.655620257 -1045.677316071 -1045.435373698 2.388625912
11 5.500000 0.236022714 274.511931925
-1045.672927474 -1045.435311187 2.788325803 12
6.000000 0.230602733 268.208091694 -1045.667489394
-1045.435199588 2.787662090... 29647 14823.500000
0.267209250 310.784186822 -1045.792584736 -1044.698640663
2.457661132 29648 14824.000000 0.263518275
306.491309460 -1045.788962431 -1044.698581242 2.866651712
29649 14824.500000 0.259648762 301.990778207
-1045.785134708 -1044.698495486 2.858745218 29650
14825.000000 0.256924523 298.822286300 -1045.782459885
-1044.698417876 2.454754142 29651 14825.500000
0.256586508 298.429150545 -1045.782209988 -1044.698378761
2.857808102 29652 14826.000000 0.259300911
301.586201573 -1045.785071671 -1044.698397266 2.856152027*
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