<div dir="ltr"><div><div><div>Dear Sir,<br><br></div>I could get the correct spin density printed on the outfile, so I think I can proceed with that. Thank u so much for replying me.<br></div><br>Sincerely,<br></div>Reshma<br></div><div class="gmail_extra"><br><div class="gmail_quote">On Mon, Jan 29, 2018 at 9:20 PM, Krack Matthias (PSI) <span dir="ltr"><<a href="mailto:matthia...@psi.ch" target="_blank">matthia...@psi.ch</a>></span> wrote:<br><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">
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<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1f497d">Dear Reshma<u></u><u></u></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1f497d"><u></u> <u></u></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1f497d">It is not fully clear to me what you want to achieve. You should provide an example (e.g. a simple test input) which shows your problem.<u></u><u></u></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1f497d"><u></u> <u></u></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1f497d">Best regards<u></u><u></u></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1f497d"><u></u> <u></u></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1f497d">Matthias<u></u><u></u></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1f497d"><u></u> <u></u></span></p>
<p class="MsoNormal"><b><span style="font-size:10.0pt;font-family:"Tahoma","sans-serif"" lang="EN-US">From:</span></b><span style="font-size:10.0pt;font-family:"Tahoma","sans-serif"" lang="EN-US"> <a href="mailto:cp...@googlegroups.com" target="_blank">cp...@googlegroups.com</a> [mailto:<a href="mailto:cp...@googlegroups.com" target="_blank">cp...@googlegroups.com</a>]
<b>On Behalf Of </b>Reshma Jose<br>
<b>Sent:</b> 29 January 2018 16:06<br>
<b>To:</b> <a href="mailto:cp...@googlegroups.com" target="_blank">cp...@googlegroups.com</a><br>
<b>Subject:</b> Re: [CP2K:9928] Re: NEL Value fixing<u></u><u></u></span></p><div><div class="h5">
<p class="MsoNormal"><u></u> <u></u></p>
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<p class="MsoNormal">Dear Sir,<u></u><u></u></p>
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<p class="MsoNormal">Thank you for your kind reply.<u></u><u></u></p>
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<p class="MsoNormal" style="margin-bottom:12.0pt">I am able to proceed four alpha and zero beta 3d electrons as an initial guess. But could not get 22 electron in case of broken symmetry approach ie mixed spin case.<u></u><u></u></p>
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<p class="MsoNormal">Thanks,<u></u><u></u></p>
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<p class="MsoNormal">Reshma<u></u><u></u></p>
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<p class="MsoNormal"><u></u> <u></u></p>
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<p class="MsoNormal">On Mon, Jan 29, 2018 at 2:26 PM, Matthias Krack <<a href="mailto:matthia...@psi.ch" target="_blank">matthia...@psi.ch</a>> wrote:<u></u><u></u></p>
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<p class="MsoNormal">Hi Reshma<br>
<br>
the &BS section is not quite intuitive. If you are looking for Cr(+2) with a 3d^4 configuration (i.e. with four alpha and zero beta 3d electrons as an initial guess), then you may try the following for the Cr kind:<br>
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<span style="font-family:"Courier New""> &BS<br>
&ALPHA<br>
N 4 3<br>
L 0 2<br>
NEL -2 3<br>
&END ALPHA<br>
&BETA<br>
N 4 3<br>
L 0 2<br>
NEL -2 -5<br>
&END BETA<br>
&END BS<br>
<br>
</span><span style="font-family:"Arial","sans-serif"">Best regards<span style="color:#888888"><br>
<br>
<span class="m_-7645476905561834432hoenzb">Matthias</span></span></span><u></u><u></u></p>
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<p class="MsoNormal"><br>
On Monday, 29 January 2018 08:00:17 UTC+1, <a href="mailto:resh...@gmail.com" target="_blank">
resh...@gmail.com</a> wrote:<u></u><u></u></p>
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<p class="MsoNormal" style="margin-bottom:12.0pt">Dear cp2k users,<br>
<br>
I am using Cr(II) based system for my calculations. I am facing problem in fixing the NEL value for Cr(II).<br>
<br>
&ALPHA<br>
NEL -2 -1<br>
L 0 2<br>
N 4 3<br>
&END ALPHA<br>
&BETA<br>
NEL -2 -1<br>
L 0 2<br>
N 4 3<br>
&END BETA<br>
<br>
I am getting correct electron count of 22 electron for Cr(II) only when above mentioned NEL combination (alpha -1 and beta -1) are used.
<br>
But with the same alpha beta values (-1,-1) I can not proceed for broken symmetry approach.<br>
Can anyone help me to fix the NEL value with which I can do broken symmetry calculations..<br>
<br>
Thanks,<br>
Reshma<u></u><u></u></p>
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