<div dir="ltr"><div><div><div><div>Dear Sir,</div><div>Thank you for your kind reply.<br></div></div>I am able to proceed
four alpha and zero beta 3d electrons as an initial guess. But could not get 22 electron in case of broken symmetry approach ie mixed spin case.<br><br></div>Thanks,<br></div>Reshma<br></div><div class="gmail_extra"><br><div class="gmail_quote">On Mon, Jan 29, 2018 at 2:26 PM, Matthias Krack <span dir="ltr"><<a href="mailto:matthia...@psi.ch" target="_blank">matthia...@psi.ch</a>></span> wrote:<br><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex"><div dir="ltr">Hi Reshma<br><br>the &BS section is not quite intuitive. If you are looking for Cr(+2) with a 3d^4 configuration (i.e. with four alpha and zero beta 3d electrons as an initial guess), then you may try the following for the Cr kind:<br><br><span style="font-family:courier new,monospace"> &BS<br> &ALPHA<br> N 4 3<br> L 0 2<br> NEL -2 3<br> &END ALPHA<br> &BETA<br> N 4 3<br> L 0 2<br> NEL -2 -5<br> &END BETA<br> &END BS<br><br><font face="arial,sans-serif">Best regards<span class="HOEnZb"><font color="#888888"><br><br>Matthias<br></font></span></font></span><div><div class="h5"><br>On Monday, 29 January 2018 08:00:17 UTC+1, <a href="mailto:resh...@gmail.com" target="_blank">resh...@gmail.com</a> wrote:<blockquote class="gmail_quote" style="margin:0;margin-left:0.8ex;border-left:1px #ccc solid;padding-left:1ex"><div dir="ltr">Dear cp2k users,<br><br>I am using Cr(II) based system for my calculations. I am facing problem in fixing the NEL value for Cr(II).<br><br> &ALPHA<br> NEL -2 -1<br> L 0 2<br> N 4 3<br> &END ALPHA<br> &BETA<br> NEL -2 -1<br> L 0 2<br> N 4 3<br> &END BETA<br><br>I am getting correct electron count of 22 electron for Cr(II) only when above mentioned NEL combination (alpha -1 and beta -1) are used. <br>But with the same alpha beta values (-1,-1) I can not proceed for broken symmetry approach.<br>Can anyone help me to fix the NEL value with which I can do broken symmetry calculations..<br><br>Thanks,<br>Reshma<br><br></div></blockquote></div></div></div><div class="HOEnZb"><div class="h5">
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