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<body class='hmmessage'><div dir='ltr'><font style="" face="Courier New,sans-serif" color="#000000">Hi, S Ling, thank you for your answer, things are starting to make much more sense now.<br>After trying the values I still have the NaN issue:<br><br>Spin 1<br><br> Guess for atomic kind: Cu1<br><br> Electronic structure<br> Total number of core electrons 18.00<br> Total number of valence electrons 15.00<br> Total number of electrons 33.00<br> Multiplicity not specified<br> S [ 2.00 2.00 2.00]<br> P [ 6.00 6.00]<br> D 15.00<br><br><br> *******************************************************************************<br> Iteration Convergence Energy [au]<br> *******************************************************************************<br> 1 0.00000 NaN<br><br> Energy components [Hartree] Total Energy :: NaN<br> Band Energy :: NaN<br> Kinetic Energy :: NaN<br> Potential Energy :: NaN<br> Virial (-V/T) :: NaN<br> Core Energy :: NaN<br> Coulomb Energy :: NaN<br> Total Pseudopotential Energy :: NaN<br> Local Pseudopotential Energy :: NaN<br> Nonlocal Pseudopotential Energy :: NaN<br> Confinement :: NaN<br><br> Orbital energies State L Occupation Energy[a.u.] Energy[eV]<br><br> 1 2 15.000 NaN NaN<br><br>---------------------------------------------------------------------------------------<br> ----------------------------------- OT ---------------------------------------<br><br> Step Update method Time Convergence Total energy Change<br> ------------------------------------------------------------------------------<br><br> Trace(PS): NaN<br> Electronic density on regular grids: NaN NaN<br> Core density on regular grids: 449.9998255599 -0.0001744401<br> Total charge density on r-space grids: NaN<br> Total charge density g-space grids: NaN<br><br>I was thinking that CP2k was starting from d10 in &ALPHA instead of d5 and from d10 in &BETA too. In this case, since I'm still getting the NaN, is it possible that something like this:<br> &KIND Cu1
<br> ELEMENT Cu
<br> BASIS_SET DZVP-MOLOPT-SR-GTH
<br> POTENTIAL GTH-PBE-q11
<br> &BS
<br> &ALPHA
<br> NEL -1 0
<br> L 0 2
<br> N 4 3
<br> &END
<br> &BETA
<br> NEL -1 -2
<br> L 0 2
<br> N 4 3
<br> &END
<br> &END
<br> &END KIND
<br> &KIND Cu2
<br> ELEMENT Cu
<br> BASIS_SET DZVP-MOLOPT-SR-GTH
<br> POTENTIAL GTH-PBE-q11
<br> &BS
<br> &ALPHA
<br> NEL -1 -2
<br> L 0 2
<br> N 4 3
<br> &END
<br> &BETA
<br> NEL -1 0
<br> L 0 2
<br> N 4 3
<br> &END
<br> &END
<br> &END KIND<br><br>Can give me the desired 5 electrons spin up and 4 spin down (and vice versa)?<br></font><br><div><font style="" face="Courier New">----------</font></div><font style="" face="Courier New" color="#666666"><b>Henrique C. S. Junior</b><br></font><div><font style="" face="Courier New" color="#666666">Químico Industrial - UFRRJ<br>Mestrando em Química Inorgânica - UFRRJ<br></font></div><div><font style="" face="Courier New" color="#666666">Centro de Processamento de Dados - PMP</font></div><br><br><div><hr id="stopSpelling">Date: Wed, 5 Aug 2015 00:53:39 +0100<br>Subject: Re: [CP2K:6868] NaN Results with &BS<br>From: lingsa...@gmail.com<br>To: cp...@googlegroups.com<br><br><div dir="ltr"><div>Hi</div><div><br></div><div>For the d9 electron configuration in a spin-polarised calculation, you should have 5 d electrons in the spin ALPHA channel, and 4 d electrons in the spin BETA channel (or 4 spin ALPHA and 5 spin BETA). Therefore, for Cu1, you should use</div><div><br></div><div>&BS<br> &ALPHA<br> NEL -1 5 #((5+5)/2=5)<br> L 0 2<br> N 4 3<br> &END<br> &BETA<br> NEL -1 3 #((5+3)/2=4)<br> L 0 2<br> N 4 3<br> &END<br>&END BS</div><div><br></div><div>and for Cu2, you should use</div><div><br></div><div>&BS<br> &ALPHA<br> NEL -1 3 #((5+3)/2=4)<br> L 0 2<br> N 4 3<br> &END<br> &BETA<br> NEL -1 5 #((5+5)/2=5)<br> L 0 2<br> N 4 3<br> &END<br>&END BS</div><div><br></div><div>SL</div></div><div class="ecxgmail_extra"><br><div class="ecxgmail_quote">On 4 August 2015 at 21:29, Henrique Junior <span dir="ltr"><<a href="mailto:henri...@gmail.com" target="_blank">henri...@gmail.com</a>></span> wrote:<br><blockquote class="ecxgmail_quote" style="border-left:1px #ccc solid;padding-left:1ex;"><div dir="ltr">
<p style="line-height:100%;" lang="en-US">Dear
CP2K group,</p>
<p style="line-height:100%;" lang="en-US">Trying
to perform a broken symmetry in a structure with two Cu(II) centers,
as I have understood from here [1] (S Ling) and here [2] (Marcella)
there is a scaling factor = 2 to take into consideration when setting
my &ALPHA and &BETA channels. Copper is [Ar] 3d10 4s1 and
since I want to get Cu(II) my goal is [Ar] 3d9 (with one unpaired
electron).</p>
<p style="line-height:100%;" lang="en-US">Taking
into account the scaling factor:
</p>
<p style="line-height:100%;" lang="en-US"><br>
</p>
<p style="line-height:100%;" lang="en-US">
&KIND Cu1</p>
<p style="line-height:100%;" lang="en-US">
ELEMENT Cu</p>
<p style="line-height:100%;" lang="en-US">
BASIS_SET DZVP-MOLOPT-SR-GTH</p>
<p style="line-height:100%;" lang="en-US">
POTENTIAL GTH-PBE-q11</p>
<p style="line-height:100%;" lang="en-US">
&BS</p>
<p style="line-height:100%;" lang="en-US">
&ALPHA</p>
<p style="line-height:100%;" lang="en-US">
NEL -1 8 <b>(because (10 + 8)/2 = 9 and I want 3d9, unpaired e-
spin up) </b>
</p>
<p style="line-height:100%;" lang="en-US">
L 0 2</p>
<p style="line-height:100%;" lang="en-US">
N 4 3</p>
<p style="line-height:100%;" lang="en-US">
&END</p>
<p style="line-height:100%;" lang="en-US">
&BETA</p>
<p style="line-height:100%;" lang="en-US">
NEL -1 -10 <b>(because (10 - 10)/2 = 0 and I want 3d0, no e-) </b>
</p>
<p style="line-height:100%;" lang="en-US">
L 0 2</p>
<p style="line-height:100%;" lang="en-US">
N 4 3</p>
<p style="line-height:100%;" lang="en-US">
&END</p>
<p style="line-height:100%;" lang="en-US">
&END</p>
<p style="line-height:100%;" lang="en-US">
&END KIND</p>
<p style="line-height:100%;" lang="en-US">
&KIND Cu2</p>
<p style="line-height:100%;" lang="en-US">
ELEMENT Cu</p>
<p style="line-height:100%;" lang="en-US">
BASIS_SET DZVP-MOLOPT-SR-GTH</p>
<p style="line-height:100%;" lang="en-US">
POTENTIAL GTH-PBE-q11</p>
<p style="line-height:100%;" lang="en-US">
&BS</p>
<p style="line-height:100%;" lang="en-US">
&ALPHA</p>
<p style="line-height:100%;" lang="en-US">
NEL -1 -10 <b>(because (10 - 10)/2 = 0 and I want 3d0, no e-) </b>
</p>
<p style="line-height:100%;" lang="en-US">
L 0 2</p>
<p style="line-height:100%;" lang="en-US">
N 4 3</p>
<p style="line-height:100%;" lang="en-US">
&END</p>
<p style="line-height:100%;" lang="en-US">
&BETA</p>
<p style="line-height:100%;" lang="en-US">
NEL -1 8 <b>(because (10 + 8)/2 = 9 and I want 3d9, unpaired e-
spin down)</b></p>
<p style="line-height:100%;" lang="en-US">
L 0 2</p>
<p style="line-height:100%;" lang="en-US">
N 4 3</p>
<p style="line-height:100%;" lang="en-US">
&END</p>
<p style="line-height:100%;" lang="en-US">
&END</p>
<p style="line-height:100%;" lang="en-US">
&END KIND</p>
<p style="line-height:100%;" lang="en-US"><br>
</p>
<p style="line-height:100%;" lang="en-US">The
results (attached) is a myriad of NaNs and 0.000000000</p>
<p style="line-height:100%;" lang="en-US">Any
ideas will be very much appreciated.</p>
<p style="line-height:100%;" lang="en-US"><br>
</p>
<p style="line-height:100%;" lang="en-US">[1] -
<a href="https://groups.google.com/forum/#%21searchin/cp2k/Broken$20symmetry/cp2k/ghhbtIxUzKk/uhwgb5PMTsgJ" target="_blank">https://groups.google.com/forum/#!searchin/cp2k/Broken$20symmetry/cp2k/ghhbtIxUzKk/uhwgb5PMTsgJ</a></p>
<p style="line-height:100%;" lang="en-US">[2] -
<a href="https://groups.google.com/forum/#%21searchin/cp2k/$26BS$20Marci/cp2k/8fTVlCEjSME/iUem9cK1-McJ" target="_blank">https://groups.google.com/forum/#!searchin/cp2k/$26BS$20Marci/cp2k/8fTVlCEjSME/iUem9cK1-McJ</a></p><span class="ecxHOEnZb"><font color="#888888">
</font></span></div><span class="ecxHOEnZb"><font color="#888888">
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