[CP2K-user] [CP2K:19430] Re: units of psi^2
Lukas C
l.cvitkovich at gmail.com
Thu Oct 26 06:30:28 UTC 2023
Hi again,
Let me please answer at least party to myself as I just figured out how to
get the dimensionless wavefunction and someone might need this at some
point.
Considering:
1. the volume V of a voxel
2. the DFT wavefunction Psi
2. that the sum of the "actual" or dimensionless wavefunction Psi_A squared
over the normalization volume V equals 1
we can say:
V * sum( Psi_A² ) = 1, where the sum goes over all voxels.
as well as:
sum( Psi² ) = F .... F is just some factor that appears due to the
normalization
we can then get the dimensionless probability density by
Psi_A²=Psi²/(V*F).
So far so good. Now I am not sure how to proceed when calcuating the
hyperfine Hamiltonian S A I, with S is the spin (here 1/2) and I is the
nuclear spin.
A is given in MHz but do i multiply this with hbar or h to get the energy?
Lukas
Lukas C schrieb am Donnerstag, 26. Oktober 2023 um 13:10:21 UTC+9:
> hi everyone!
>
> I am using the cp2k implementation to calculate hyperfine tensors. no
> problems here so far, i got some results using an all-electron basis set.
>
> now, unfortunately, i cannot find any information on how this is done
> internally and also i cannot assign the units. e.g. in which units is
> |Psi(x,y,z)|^2 ? I know that it has to be normalized, but to which volume?
>
> one starting point was the vasp manual, in which they clearly say how the
> calculations works. https://www.vasp.at/wiki/index.php/LHYPERFINE
>
> does cp2k work similarly?
>
> Thank you!
>
> Best,
> Lukas
>
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