[CP2K-user] [CP2K:18243] Re: How to speed HF up
Augustin Bussy
augustin.bussy at chem.uzh.ch
Thu Dec 22 11:30:51 UTC 2022
Hi Dobromir,
you should keep in mind that HFX is inherently an expensive method (compared to GGA). From your input file, I would say you are already using all the tricks I know of:
1. Using the ADMM method
2. Using a truncated Coulomb operator, although I have to warn you about using extreme values such as 2.0 Angstrom (~6 is usually good)
3. Using the largest possible value for MAX_MEMORY
4. Using a loose EPS_SCHWARZ threshold. Here too, 1.0E-6, may be on the limit
Also, I think that your EPS_DEFAULT value might be dangerously loose, if you want accurate results. You could optionally try to use the RI-HFX method by adding the &RI subsection in &HF. Default parameters should be good enough. There is however no guarantee that it speeds up you particular calculation.
Best,
Augustin
________________________________
From: cp2k at googlegroups.com <cp2k at googlegroups.com> on behalf of DMT <dobromirak at gmail.com>
Sent: Thursday, December 22, 2022 12:02 PM
To: cp2k <cp2k at googlegroups.com>
Subject: [CP2K:18243] Re: How to speed HF up
I tried
!&PBE_HOLE_T_C_LR
! CUTOFF_RADIUS 6.0
! SCALE_X 0.25
!&END PBE_HOLE_T_C_LR
in &XF_FUNCTIONAL and
&HF
FRACTION 0.25
&SCREENING
EPS_SCHWARZ 1.0E-6 !DEFAULT 1.0E-10, TYPICAL -6 - -9, FOR STABLE HFX
!SCREEN_ON_INITIAL_P T !FOR A GOOD INITIAL GUESS FROM A .WFN
&END SCREENING
&INTERACTION_POTENTIAL
POTENTIAL_TYPE TRUNCATED !TRUNCATED 1/r (Coulomb) POTENTIAL FOR SPEED UP
CUTOFF_RADIUS 6.0 !SHOULD BE < HALF THE CELL
T_C_G_DATA /home/lsd/cp2k_data/t_c_g.dat !DATA FOR THE EVAL OF TRUNCATED GAMMA FUNC
&END INTERACTION_POTENTIAL
in &XC and there is no significant (if any) speed up.
I even played with the CUTOFF_RADIUS (values from 2.0 to 6.0) and nothing changes.
Am I missing something ?
Best Regards,
Dobromir
On Tuesday, December 20, 2022 at 8:31:44 PM UTC+2 DMT wrote:
Hello,
I have heard that there must be a way to speed HF (for hybrid DFT methods) up. Can you help me with that ?
Best Regards,
Dobromir
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