[CP2K:10592] Clarification on cell size and range
hut... at chem.uzh.ch
hut... at chem.uzh.ch
Thu Aug 2 07:07:08 UTC 2018
Hi
the size of the cell is in your case 10.8649^3 as defined in the input.
Because there is translational invariance, the position of the cell
is not defined. Internally, CP2K works with a computational cell
defined by
x = x - A * NINT(x/A)
Some calculations are done in other cells, e.g. the plane wave
expansions.
Atomic positions during MD/Geometry optimization are not folded
back for output (only internally for the force calculation).
regards
Juerg Hutter
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Juerg Hutter Phone : ++41 44 635 4491
Institut für Chemie C FAX : ++41 44 635 6838
Universität Zürich E-mail: hut... at chem.uzh.ch
Winterthurerstrasse 190
CH-8057 Zürich, Switzerland
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-----cp... at googlegroups.com wrote: -----
To: "cp2k" <cp... at googlegroups.com>
From: gaston.... at gmail.com
Sent by: cp... at googlegroups.com
Date: 08/01/2018 03:27PM
Subject: [CP2K:10592] Clarification on cell size and range
Hi everybody,
I am new to CP2K and I atrying to understand a few things about the cell :
What is the size of the cell and it's range?
With the following part of the input file (more attached)
&CELL
SYMMETRY CUBIC
A 10.86490000 0.000000000 0.000000000
B 0.000000000 10.86490000 0.000000000
C 0.000000000 0.000000000 10.86490000
&END CELL
I get negative positions in [-10.86490000 ; +10.86490000] while running an MD simulation with positive initial positions.
Does that mean that the cell ranges from -10.86490000 to +10.86490000??
On the other hand in the output file I get the following message :
CELL_TOP| Volume [angstrom^3]: 1282.559
CELL_TOP| Vector a [angstrom 10.865 0.000 0.000 |a| = 10.865
CELL_TOP| Vector b [angstrom 0.000 10.865 0.000 |b| = 10.865
CELL_TOP| Vector c [angstrom 0.000 0.000 10.865 |c| = 10.865
The volume here is 1282.559 = 10.865^3
This seems to indicate that the cell ranges from 0 to +10.8650000!!
Can anyone clarify this point please?
Thanks
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[attachment "run.inp" removed by Jürg Hutter/at/UZH]
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