Remove fixed_atoms after few steps during optimization
Sandeep Kumar Reddy
kuma... at gmail.com
Wed Mar 28 08:56:27 UTC 2012
Dear all,
I have a problem in restarting the optimization job. For
illustrating this, i have taken simple input file which runs faster (within
a minute).
Initially, geometry optimization is performed by fixing atomic positions
of few atoms and then, do optimization with no constraints.
For restarting the job, i have set the following keywords as follows :
%MOTION%CONSTRINTS to OFF and %EXT_RESTART%RESTART_CONSTRAINT F,
But, still atoms are under constraint. Am i doing anything wrong in
restarting the job ?
(Files are enclosed if you want to re-run the job)
I have fixed the position of atom 1.
&GLOBAL
PROJECT H2O-fixed
RUN_TYPE GEO_OPT
PRINT_LEVEL LOW
&END GLOBAL
&EXT_RESTART
RESTART_FILE_NAME H2O-fixed-1.restart
* RESTART_CONSTRAINT F*
&END EXT_RESTART
&MOTION
&GEO_OPT
RMS_FORCE 1.0D-6
MAX_ITER 4
&END
&CONSTRAINT *OFF *
&FIXED_ATOMS
LIST 1
&END FIXED_ATOMS
&END CONSTRAINT
&PRINT
&STRUCTURE_DATA
POSITION 1
POSITION 2
POSITION 3
&END STRUCTURE_DATA
&END PRINT
&END MOTION
&FORCE_EVAL
METHOD QS
&DFT
BASIS_SET_FILE_NAME BASIS_SET
POTENTIAL_FILE_NAME POTENTIAL
&MGRID
CUTOFF 200
&END MGRID
&QS
EPS_DEFAULT 1.0E-8
EXTRAPOLATION use_prev_p
&END QS
&SCF
EPS_SCF 1.0E-5
SCF_GUESS ATOMIC
&END SCF
&XC
&XC_FUNCTIONAL Pade
&END XC_FUNCTIONAL
&END XC
&END DFT
&SUBSYS
&CELL
ABC 5.0 5.0 5.0
&END CELL
&COORD
O 0.000000 0.000000 -0.065587
H 0.000000 -0.757136 0.520545
H 0.000000 0.757136 0.520545
&END COORD
&KIND H
BASIS_SET DZV-GTH-PADE
POTENTIAL GTH-PADE-q1
&END KIND
&KIND O
BASIS_SET DZVP-GTH-PADE
POTENTIAL GTH-PADE-q6
&END KIND
&PRINT
&STRUCTURE_DATA
POSITION 1
POSITION 2
POSITION 3
DISTANCE 1 2
DISTANCE 1 3
ANGLE 2 1 3
&END STRUCTURE_DATA
&END PRINT
&END SUBSYS
&END FORCE_EVAL
H2O-fixed-pos-1.xyz file :
*With constraint :*
3
i = 1, E = -17.1523810980
O 0.0000000000 0.0000000000 -0.0655870000
H 0.0000000011 -0.7636945745 0.5251374879
H 0.0000000009 0.7636945752 0.5251374874
3
i = 1, E = -17.1523810980
O 0.0000000000 0.0000000000 -0.0655870000
H 0.0000000011 -0.7636945745 0.5251374879
H 0.0000000009 0.7636945752 0.5251374874
3
i = 2, E = -17.1524730195
O 0.0000000000 0.0000000000 -0.0655870000
H 0.0000000032 -0.7691426930 0.5290280193
H 0.0000000025 0.7691426947 0.5290280176
*After removing constraint :*
3
i = 3, E = -17.1524733267
O 0.0000000000 0.0000000000 -0.0655870000
H 0.0000000044 -0.7692971251 0.5292081412
H 0.0000000034 0.7692971274 0.5292081389
3
i = 4, E = -17.1524734666
O 0.0000000000 0.0000000000 -0.0655870000
H 0.0000000071 -0.7694391730 0.5294545586
H 0.0000000055 0.7694391765 0.5294545548
Thanks in advance for your suggestions.
Regards,
Sandeep
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